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451.104

$a^4-4a^2b^2-1+4ab=$
$=a^4-(4a^2b^2+1-4ab)=$
$=a^4-(2ab-1)^2$

$x^4-16x^2y^2-16-32xy=$
$=x^4-(16x^2y^2+16+32xy)=$
$=x^4-(4xy+4)^2=$
$=(x^2+2xy+2)*(x^2-2xy-2)$

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