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AndreaTrapezio
R---A--B
|.......\
|........C
|...O.....\
|..........\
P---H-------E
Dati:BC=9 CE=16 2p=? Area=?
Svolgimento:raggio tg in A e C --> AO cg AC + OAB cg OCB+ OB comune ----> AB cg BC = 9
r= (2° Euclide: h2=pc1*pc2= 9*16=144 --> r=12;
OE=radice(OC^2+CE^2)=radice(12^2+16^2)=radice(144+256)=radice(400)=20
HE=radice(OE^2-OH^2)=radice(400-144)=radice(256)=16
2p=RA+AB+BC+CE+EH+HP+PR
2p=12+9 +9+ 16+16+12+24=24+18+32+24=48+50=98
A=(bm+bM)*h / 2= (12+9)*(12+16)*24/2 = 21*28=280+280+28=560+28=588
giovanni - 22/2/05 - 07:07 pm
giovanni - 22/2/05 - 07:07 pm
giovanni - 22/2/05 - 07:06 pm
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